Welcome to a deep dive into the fascinating world of Data Structures and Algorithms! Today, we'll be exploring Infix to Prefix Conversion, a crucial concept that will help you navigate complex mathematical and programming expressions.
Before we dive into the conversion process, let's familiarize ourselves with Infix and Prefix Notations.
Infix notation is a way of representing mathematical operations between operands, such as 2 + 3. The operators are placed between the operands.
Prefix notation, also known as Polish notation, places the operator before the operands, like + 2 3. This notation simplifies the evaluation order and can be more easily parsed by computers.
Converting infix notation to prefix notation is essential for parsing complex mathematical and programming expressions, especially when dealing with functions and multiple operators.
We'll be using a simple algorithm for conversion:
( 1 + 2 ) * 3 š”Let's convert the infix expression ( 1 + 2 ) * 3 to prefix notation using our algorithm.
* has higher precedence than +, so we'll evaluate the addition first.* ( + 1 2 ) 3Now, let's implement the conversion algorithm in Python and Java to make it practical.
def convert_to_prefix(infix):
precedence = {'+': 1, '-': 1, '*': 2, '/': 2, '^': 3}
prefix = []
parentheses_stack = []
operands_stack = []
for token in infix:
if token.isalnum():
operands_stack.append(token)
elif token in ['(', ')']:
parentheses_stack.append(token)
while parentheses_stack and parentheses_stack[-1] == '(':
operation = parentheses_stack.pop()
operands_stack.append(operation)
elif token in ['+', '-', '*', '/', '^']:
while parentheses_stack and parentheses_stack[-1] != '(' and precedence[parentheses_stack[-1]] >= precedence[token]:
operation = parentheses_stack.pop()
right_operand = operands_stack.pop()
left_operand = operands_stack.pop()
prefix.append(operation + ' ' + left_operand + ' ' + right_operand)
parentheses_stack.append(token)
while parentheses_stack:
operation = parentheses_stack.pop()
operands_stack.append(operation)
while operands_stack:
prefix.append(operands_stack.pop())
return ' '.join(prefix)
print(convert_to_prefix('( 1 + 2 ) * 3')) # Output: * ( + 1 2 ) 3import java.util.Stack;
public class InfixToPrefix {
static int precedence(char op) {
switch (op) {
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
default:
return -1;
}
}
static String infixToPrefix(String exp) {
String prefix = "";
Stack<Character> s = new Stack<>();
for (int i = 0; i < exp.length(); i++) {
char symbol = exp.charAt(i);
if (Character.isLetter(symbol) || Character.isDigit(symbol))
prefix += symbol + " ";
if (symbol == '(')
s.push(symbol);
else if (symbol == ')') {
char topSymbol = s.peek();
while (topSymbol != '(') {
prefix += topSymbol + " ";
s.pop();
topSymbol = s.peek();
}
s.pop();
}
else if (s.isEmpty() || precedence(s.peek()) < precedence(symbol))
s.push(symbol);
else {
char topSymbol = s.peek();
while (!s.isEmpty() && precedence(topSymbol) >= precedence(symbol)) {
prefix += topSymbol + " ";
s.pop();
if (!s.isEmpty())
topSymbol = s.peek();
}
s.push(symbol);
}
}
while (!s.isEmpty()) {
char topSymbol = s.peek();
if (topSymbol == '(') break;
prefix += topSymbol + " ";
s.pop();
}
return prefix;
}
public static void main(String[] args) {
String exp = "( 1 + 2 ) * 3";
System.out.println(infixToPrefix(exp)); // Output: * ( + 1 2 ) 3
}
}Which of the following is a valid prefix notation for the infix expression `( ( 1 + 2 ) * 3 ) + 4`?