Welcome to LeetCode, a popular platform for honing your Data Structures and Algorithms skills! In this comprehensive guide, we'll explore LeetCode's features, learn how to navigate the platform, and practice with examples. Let's dive in! š
LeetCode is an online platform where you can practice programming challenges, primarily focusing on Data Structures and Algorithms. It's a great tool for developers to upskill, prepare for interviews, or simply test their problem-solving abilities.
Some common data structures and algorithms you'll encounter on LeetCode are:
Here are two practice problems to get you started:
Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target. You may assume that each input would have exactly one solution, and you may not use the same element twice.
def twoSum(nums, target):
# Create a dictionary to store numbers as keys and their indices as values
num_dict = {}
for i, num in enumerate(nums):
# If the difference between the target and the current number exists in the dictionary, return the indices
if target - num in num_dict:
return [num_dict[target - num], i]
else:
# Add the current number and its index to the dictionary
num_dict[num] = i
# Example usage:
nums = [2, 7, 11, 15]
target = 9
print(twoSum(nums, target)) # Output: [0, 1]Given a string s, find the length of the longest substring without repeating characters.
def lengthOfLongestSubstring(s):
# Initialize start and end indices of the current substring
start = 0
end = 0
# Initialize the maximum length found so far
max_length = 0
# Create a dictionary to store characters and their last occurrence indices
char_dict = {}
while end < len(s):
# If the character at the end of the current substring is already in the dictionary, move the start index to the right of the last occurrence of that character
if s[end] in char_dict and char_dict[s[end]] >= start:
start = char_dict[s[end]] + 1
# Update the end index and store the character in the dictionary with its current index
char_dict[s[end]] = end
end += 1
# Update the maximum length if the current substring is longer
max_length = max(max_length, end - start)
return max_length
# Example usage:
s = "abcabcbb"
print(lengthOfLongestSubstring(s)) # Output: 3What is LeetCode primarily focused on?
Happy learning, and keep coding! š»