Welcome to a fascinating journey through one of the most intriguing problems in computer science ā The Skyline Problem! This problem is a great way to dive deep into data structures and algorithms, and we'll learn it step-by-step, just like building a skyscraper. šļø
Imagine you're an architect designing a city skyline. Your task is to find all the unique "visible" buildings' edges from different viewpoints. The challenge lies in sorting and merging the buildings' heights and positions to get the final skyline. Sounds interesting, right? Let's dive in!
Before we start, you should be familiar with the following concepts:
Given a list of buildings, each building i is described by an array [Li, Ri, Hi], where:
We are now ready to find all unique "visible" points in the skyline. For each viewpoint (x, y), we search for the highest building with left edge less than or equal to x and right edge greater than x. The y-coordinate of the point is the maximum height among all such buildings.
We'll tackle the problem in three steps:
Let's break down each step and see how it works.
First, we need to sort all buildings by their left x-coordinates in non-decreasing order. This step is crucial as it makes finding the highest building for each x-coordinate easier during the merging process.
Here's a simple way to sort the buildings using Selection Sort:
def selection_sort(buildings):
for i in range(len(buildings)):
min_index = i
for j in range(i+1, len(buildings)):
if buildings[j][0] < buildings[min_index][0]:
min_index = j
buildings[i], buildings[min_index] = buildings[min_index], buildings[i]š” Pro Tip: Selection Sort is not the most efficient sorting algorithm, but it's easy to understand and implement. As you progress in your learning, you'll encounter more efficient algorithms like Merge Sort and Quick Sort.
Once the buildings are sorted, we can start merging them using two pointers. Initially, we maintain two pointers: left and right, which point to the current buildings with left edges less than or equal to the current x-coordinate and greater than the current x-coordinate, respectively.
def merge_buildings(buildings):
merged_buildings = []
x = buildings[0][0]
left_index = 0
for right_index in range(1, len(buildings)):
if buildings[right_index][0] > x:
merged_buildings.append(buildings[left_index])
left_index += 1
x = max(x, buildings[right_index][1])
merged_buildings.append(buildings[left_index:])
return merged_buildingsNow that we have the merged buildings, we need to process them to find the visible points. We'll maintain a list of visible points and update it whenever we find a new point or a height change for the current point.
def find_skyline(buildings):
merged_buildings = merge_buildings(buildings)
visible_points = []
for buildings_part in merged_buildings:
if len(buildings_part) > 0:
current_height = buildings_part[0][2]
current_x = buildings_part[0][0]
visible_points.append((current_x, current_height))
for building in buildings_part[1:]:
if building[2] > current_height:
visible_points.append((building[0], building[2]))
current_height = building[2]
elif building[0] < current_x and building[2] < current_height:
pass # No need to update if the new building is not visible
else:
current_height = building[2]
return visible_pointsGiven the following buildings:
Congratulations! You've now learned how to solve The Skyline Problem using data structures and algorithms. As you practice more, you'll find more efficient ways to solve this problem, but for now, you have a solid foundation to build upon.
š Note: Keep exploring, keep coding, and keep learning! Happy coding! š©āš»š