Welcome to this comprehensive guide on finding the two sum problem in a Binary Search Tree (BST)! We'll walk through the problem, understand why it's important, and learn how to solve it with practical examples. Let's dive in!
In this lesson, we'll learn to find a pair of nodes in a Binary Search Tree (BST) that add up to a given sum. This problem is a common question during technical interviews and is an essential concept in data structures and algorithms.
Before diving into the Two Sum problem in BST, make sure you're familiar with the following topics:
Given a Binary Search Tree (BST) and an integer targetSum, find a pair of nodes in the tree whose values add up to the targetSum.
To solve the Two Sum problem in a BST, we can use the Inorder Traversal property of BSTs and recursion.
currentSum and compare each node's value with targetSum - currentSum. If they are equal, we've found the desired pair.currentSum + node.value is less than targetSum, update currentSum and move to the right subtree.currentSum + node.value is greater than targetSum, move to the left subtree.Let's consider the following BST:
5
/ \
3 7
/\ /\
2 4 6 8
To find a pair that adds up to 9, we'll traverse the tree as follows:
targetSum - 5 (i.e., 4) is greater than 2 (3, the left child of 5), move to the left subtree.targetSum - 3 (i.e., 6) is less than 5 (the right child of 3), move to the right subtree.targetSum - 2 (i.e., 7) is less than 7 (the right child of 3), move to the right subtree.targetSum - 4 (i.e., 5) equals the current node's value (4), we've found the desired pair (4, 5).Here's a Python implementation of the Two Sum problem in a BST:
class Node:
def __init__(self, key):
self.left = None
self.right = None
self.val = key
def findPairWithGivenSum(root, targetSum):
def helper(node, currentSum):
if not node:
return False
if currentSum < targetSum:
return helper(node.right, currentSum + node.val)
if currentSum > targetSum:
return helper(node.left, currentSum + node.val)
return True
return helper(root, 0)
# Test the function
root = Node(5)
root.left = Node(3)
root.right = Node(7)
root.left.left = Node(2)
root.left.right = Node(4)
root.right.left = Node(6)
root.right.right = Node(8)
print(findPairWithGivenSum(root, 9)) # True (Found: (4, 5))In the Two Sum problem in a BST, what is the purpose of maintaining a `currentSum` variable?
That's it for today! By learning how to solve the Two Sum problem in a Binary Search Tree, you've taken a significant step towards mastering important data structures and algorithms concepts. Keep practicing and happy coding! š¤āØ